0=64p^2-9

Solution for 0=64p^2-9 equation:

0=64p^2-9

We move all terms to the left:

0-(64p^2-9)=0

We add all the numbers together, and all the variables

-(64p^2-9)=0

We get rid of parentheses

-64p^2+9=0

a = -64; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-64)·9
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*-64}=\frac{-48}{-128}
=3/8
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*-64}=\frac{48}{-128}
=-3/8
$